execute1: Fix interrupt delivery during slow instructions

During slow instructions such as multiply or divide, if a decrementer
(or other asynchronous) interrupt becomes pending, it disrupts the
logic that keeps stall asserted until the end of the slow
instruction, and the interrupt logic starts trying to deliver the
interrupt before the slow instruction has finished.

To fix that, make the interrupt logic wait until it sees e_in.valid
set before setting exception to 1.

Signed-off-by: Paul Mackerras <paulus@ozlabs.org>
pull/166/head
Paul Mackerras 5 years ago
parent fe789190e4
commit 102fbcfe9a

@ -454,12 +454,12 @@ begin
v.e.valid := e_in.valid;
report "Writing SRR1: " & to_hstring(ctrl.srr1);

elsif irq_valid = '1' then
elsif irq_valid = '1' and e_in.valid = '1' then
-- we need two cycles to write srr0 and 1
-- will need more when we have to write DSISR, DAR and HIER
-- Don't deliver the interrupt until we have a valid instruction
-- coming in, so we have a valid NIA to put in SRR0.
exception := e_in.valid;
exception := '1';
ctrl_tmp.srr1 <= msr_copy(ctrl.msr);

elsif e_in.valid = '1' and ctrl.msr(MSR_PR) = '1' and

Loading…
Cancel
Save